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Solution 3-3
A) The number of bits is
1980 * 1050 * 24 = 4.99 * 10^7
B) Given the transmit rate of the modem as 14,400 bits per second, the time to transmit this is
t = L/C = 4.99 * 10^7 / 1.44 * 10^4 = 3.465 * 10^3 sec
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